find the empirical formula for oxide that contains 42.05g of Nitrogen and 95.95g of oxygen
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Answer:
weight of nitrogen =42.05g
- moles=3.004
weight of oxygen =95.95
- moles=5.996
- simplest ratio,
- of O 5.996/3.04=1.99=2(approx)
- of N 5.5996/5.996=1
therefore, empirical formula is NO2
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