Question

find the empirical formula of the compound with the followinf percentage composition ; Pb = 62.5% , N = 8.5%, O= 29%

Answer 1

atomic mass of Pb = 207 g/mol

atomic mass of N = 14 g/mol

atomic mass of O = 16 g/mol

percentage composition:

Pb = 62.5% , N = 8.5% and O = 29%

Now finding percentage mass ratio,

Pb ⇒ 62.5/207 = 0.3063

N ⇒ 8.5/14 = 0.6071

O ⇒ 29/16 = 1.8125

finding simple ratio of given elements,

Pb : N : O : : 0.3063 : 0.6071 : 1.8125

⇒Pb : N : O : : 0.3 : 0.6 : 1.8

⇒ Pb : N : O : : 1 : 2 : 6

hence, empirical formula of compound is $PbN_2O_6$

Answer 2

Answer:

atomic mass of Pb = 207 g/mol

atomic mass of N = 14 g/mol

atomic mass of O = 16 g/mol

percentage composition:

Pb = 62.5% , N = 8.5% and O = 29%

Now finding percentage mass ratio,

Pb ⇒ 62.5/207 = 0.3063

N ⇒ 8.5/14 = 0.6071

O ⇒ 29/16 = 1.8125

finding simple ratio of given elements,

Pb : N : O : : 0.3063 : 0.6071 : 1.8125

⇒Pb : N : O : : 0.3 : 0.6 : 1.8

⇒ Pb : N : O : : 1 : 2 : 6

hence, empirical formula of compound is PbN_2O_6PbN

2

O

6