Question

Find the energy associated with excitation of electron of hydrogen atom if it excites from n=2 to

n=4. (RH = 2.18x10-18)​

Answer 1

Explanation:

The expression for the wavelength of radiation is,

λ

1

=R(

n

1

2

1

−

n

2

2

1

)

Substitute values in the above expression,

λ

1

=109677×(

2

2

1

−

4

2

1

)=109677×(

4

1

−

16

1

)=109677×(

64

12

)

λ=4.86×10

−5

cm=486×10

−9

m=486nm.

The line belongs to bluish green colour.