Question

Find the energy dissipated in 5 minutes by an electric bulb with a filament of resistance of 500Ω connected to a 240V supply.

Answer 1

Answer:

3.6x10^7

Explanation:

power(P)=VR

t=5*60=300 seconds

P= 240*500

E=P*t

E= 240*500*300

E= 3.6x10

Answer 2

Answer:

3.456 × 10^4

Explanation:

P=V2/R

P=(240×240)\500

P = 1.152 × 10^2

E = P × t

E = ( 1.152 × 10^2)×5×60

E = 3.456 × 10^4