Chemistry, asked by radz7, 2 months ago

Find the energy in kJ for an x-ray photon with a wavelength of 5.89 × 10-7 m​

Answers

Answered by anthonypaulvilly
0

Answer:

   E = 3.395 × 10⁻¹⁹ J per atom

Explanation:

Wavelength (λ) = 5.89 × 10⁻⁷ m​

E = nhc / λ

E - energy

n - number of photons

h - plancks constant = 6.626×10⁻³⁴

c - speed of light = 3 × 10⁸

E = 1 × 6.626×10⁻³⁴ × 3 × 10⁸ / 5.89 × 10⁻⁷

E = 20 × 10⁻²⁶ / 5.89 × 10⁻⁷

E = 3.395 × 10⁻¹⁹ j per atom

E = 3.395 × 10⁻¹⁹ J per atom

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