Find the energy in kJ for an x-ray photon with a wavelength of 5.89 × 10-7 m
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Answer:
E = 3.395 × 10⁻¹⁹ J per atom
Explanation:
Wavelength (λ) = 5.89 × 10⁻⁷ m
E = nhc / λ
E - energy
n - number of photons
h - plancks constant = 6.626×10⁻³⁴
c - speed of light = 3 × 10⁸
E = 1 × 6.626×10⁻³⁴ × 3 × 10⁸ / 5.89 × 10⁻⁷
E = 20 × 10⁻²⁶ / 5.89 × 10⁻⁷
E = 3.395 × 10⁻¹⁹ j per atom
E = 3.395 × 10⁻¹⁹ J per atom
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