Question

find the energy in KWh consumed in 24 hours by 2 electic devices , one of 100W and other of 500W​

Answer 1

total time is equal to 24 hours now total power is equal to 2 x + 2 x 500 is equal to 200 + 2000 is equal to 1200 now Total energy consumed is equal to 1200 watt x 24 hour is equal to 28800 what are now is that is equal to 2 8.8 kilowatt hour

Answer 2

The energy consumed by the 2 electric devices is 2.4 kWh and 12 kWh respectively.

Explanation:

Given that,

The power of 1st electric device, $P_1=100\ W$

The power of 2nd electric device, $P_2=500\ W$

The power of an electrical device is given by the electrical energy consumed per unit time such that :

$P=\dfrac{E}{t}$

Here t = 24 hours

So,

$E=P\times t$

For first device :

$E_1=P_1\times t$

$E_1=100\ W\times 24\ h$

$E_1=2400\ Wh$

or

$E_1=2.4\ kWh$

For second device

$E_2=P_2\times t$

$E_2=500\ W\times 24\ h$

$E_2=12000\ Wh$

or

$E_2=12\ kWh$

So, the energy consumed by the 2 electric devices is 2.4 kWh and 12 kWh respectively.

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Electric power

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