Question

Find the energy in kWh consumed in 24 hours by two electric devices, one of 100 W and other of 500 W ?

Answer 1

Energy (in kWh) =14.4

Answer 2

The energy consumed due to first and second electrical device is 2.4 kWh and 12 kWh respectively.

Explanation:

It is given that,

Power of first electrical device, $P_1=100\ W$

Power of second electrical device, $P_2=500\ W$

Time, t = 24 hours

We need to find the energy consumed by these two electrical devices. Power of an electrical device is given by :

$P=\dfrac{energy\ consumed}{time}$

$E=P\times t$

Electrical energy consumed due to first device is,

$E_1=P_1\times t$

$E_1=100\ W\times 24\ h$

$E_1=2400\ Wh$

or

$E_1=2.4\ kWh$

Electrical energy consumed due to second device is,

$E_2=P_2\times t$

$E_2=500\ W\times 24\ h$

$E_2=12000\ Wh$

or

$E_2=12\ kWh$

So, the energy consumed due to first and second electrical device is 2.4 kWh and 12 kWh respectively.  Hence, this is the required solution.

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