Question

Find the energy lost when the charge capacitor is disconnected from the source and connected with parallel with the uncharged capacitor .where does this lose of energy appear

Answer 1

Answer:

Q=Q

1

+Q

2

V

1

=V

2

potential of both capacitors after they are connected with each other.

∴

C

1

Q

1

=

C

2

Q

2

⇒ Q=(

C

2

+1

C

1

)Q

2

Q

2

=

C

1

+C

2

QC

2

Q

1

=

C

1

+C

2

QC

2

The lost energy appears in the form of heat.