find the energy of a photon with 4000A° wavelength in water
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Answer:
E=hr(r=frequency)
=h x c/λ
=6.626 x 10^-34 x 3 x 10^8 x 4000 x 10^-10
=19.878 x 10^-34/40
=0.49655 x 10^-34 m
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Answered by
1
Answer:
Hey Buddy here's ur answer
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