find the energy of an electron moving in one dimension in an infinitely high potential box of width 0.1nm
Answers
Answer:
Eight values given here of the particles present in the 1 Directional box of the value of the different energy and radiation levels of various states are
shown by the representative n or quantum number =
The Energy level for nth state
= En
= [ h2 / ( 8 m L2 ) ] n2
where h = 6.626 × 10-34 J , or planck's constant
m = 9.109 × 10-31 kg ,
electron mass
L = 10-10 m
= dimension of box
n is the quantum of state
By substituting the values for the given,
we get,
En
= 6.025 × 10-18 n2 J
since 1 eV = 1.602 × 10-19 J ,
we express energy of states in eV as,
En = (6.025 × 10-18 n2 ) / ( 1.602 × 10-19 ) eV
En = 37.61 n2 eV
Hence ,
E1 = 37.61 eV
E2
= 37.61 × 4
= 150.44 eV
E3
= 37.61 × 9
= 338.5 eV
E4
= 37.61 × 16
= 601.76 eV
Explanation:
That amount of energy required to transfer an electrons through one zone to another, according to Bohr, is a set, finite amount. Energy levels are the names for these areas.
At the lower energy level, which is also the state most near the atomic centre.
A object in motion or particle has kinetic energy, which depends on both its mass and its rate of motion.
Atoms' kinetic and potential energies are produced by the motion of their electrons. When excited, electrons migrate to an orbital with a higher energy level that is further from the atom.
The kinetic and potential of an electrons at that energetic level increases with the distance of the orbital from the nucleus.
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