Question

find the energy possessed by an object of mass 10 kg when it is at a height of 6 cm above the ground .​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Energy\:possessed=6\:J}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline{\bold{Given:}}} \\ \tt: \implies Mass \: of \: body (m)= 10 \: kg \\ \\ \tt: \implies Height(h) = 6 \: cm \\ \\ \red{\underline{\bold{To \: Find:}}} \\ \tt: \implies Energy \: possessed =?$

• According to given question :

$\green{ \star } \tt \: Height = \frac{6}{100} = 0.06 \: m \\ \\ \green{\star } \tt \: g = 10 \: {m/s}^{2} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Kinetic \: Energy = \frac{1}{2} m {v}^{2} \\ \\ \tt: \implies Kinetic \: Energy = \frac{1}{2} \times 10 \times {0}^{2} \\ \\ \tt: \implies Kinetic \: Energy =0 \: J- - - - - (1) \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Potential\: Energy =mgh \\ \\ \tt: \implies Potential\: Energy =10 \times 10 \times 0.06 \\ \\ \tt: \implies Potential\: Energy =6 \: J - - - - - (1) \\ \\ \text{Adding \: (1) \: and \: (2)} \\ \\ \tt: \implies Energy \: possessed = K.E + P.E \\ \\ \tt: \implies Energy \: possessed =0 + 6 \\ \\ \green{\tt: \implies Energy \: possessed =6 \: J}$

Answer 2

Answer:

6 J

Explanation:

$\underline{\bigstar\:\textsf{Given:}}$

• Mass of object (m) = 10 kg
• Height (h) = 6 cm = 0.06 m

$\underline{\bigstar\:\textsf{To\:find:}}$

• Energy possessed by that object (E) = ?

$\underline{\bigstar\:\textsf{Given:}}$

Let's take analysis of the situation first !

There is an object whose mass is 10 kg and it is at a height of 0.06 m. We have to calculate the energy possessed by that object.

Let's find now !

We know, an object has both kinetic and potential energies or mechanical energy.

(Mechanical energy = P.E + K.E)

▪︎ We remember, $\blue\:\sf{K.E\:=\:\dfrac{1mv^2}{2}}$

(here, v = 0)

$\implies\:\sf{K.E\:=\:\dfrac{1\:×\:10\:×\:0^2}{2}}$

$\implies$ K.E = 5 × 0

So, K.E = 0 Joules

▪︎We also remembers, Potential energy (P.E) = mgh

(g = 9.8 m/s²)

$\implies$ P.E = 10 × 9.8 × 0.06

$\implies$ P.E = 98 × 0.06

$\implies$ P.E = 5.88 J

Thus, P.E = 5.88 Joules.

Now, total energy possessed = P.E + K.E

$\longrightarrow$ 5.88 + 0

${\large{\boxed{\sf{\therefore \:Energy\:possessed\:is\:5.88\:J}}}}$

(If we will take g as 10 then energy possessed will be 6 J)

Hope it helped you dear...