Find the energy possessed by an object of mass 10 kg when it is at a height of 6m above the ground given g=9.8ms_2
Answers
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________
AT SOME HEIGHT GIVEN...
SO USE THE FORMULA OF POTENTIAL ENERGY
= MGH
= 10 X9.8 X 6
= 588 JOULE
HOPE IT WILL HELP YOU
Answer:
6 J
Explanation:
\underline{\bigstar\:\textsf{Given:}}
★Given:
Mass of object (m) = 10 kg
Height (h) = 6 cm = 0.06 m
\underline{\bigstar\:\textsf{To\:find:}}
★Tofind:
Energy possessed by that object (E) = ?
\underline{\bigstar\:\textsf{Given:}}
★Given:
Let's take analysis of the situation first !
There is an object whose mass is 10 kg and it is at a height of 0.06 m. We have to calculate the energy possessed by that object.
Let's find now !
We know, when an object has both kinetic and potential energies or mechanical energy.
(Mechanical energy = P.E + K.E)
▪︎ We remember, \blue\:\sf{K.E\:=\:\dfrac{1mv^2}{2}}K.E=
2
1mv
2
(here, v = 0)
\implies\:\sf{K.E\:=\:\dfrac{1\:×\:10\:×\:0^2}{2}}⟹K.E=
2
1×10×0
2
\implies⟹ K.E = 5 × 0
So, K.E = 0 Joules
▪︎We also remembers, Potential energy (P.E) = mgh
(g = 9.8 m/s²)
\implies⟹ P.E = 10 × 9.8 × 0.06
\implies⟹ P.E = 98 × 0.06
\implies⟹ P.E = 5.88 J
Thus, P.E = 5.88 Joules.
Now, total energy possessed = P.E + K.E
\longrightarrow⟶ 5.88 + 0
{\large{\boxed{\sf{\therefore \:Energy\:possessed\:is\:5.88\:J}}}}
∴Energypossessedis5.88J
(If we will take g as 10 then energy possessed will be 6 J)
Hope it helped you dear...