Find the energy spent in spraying a drop of mercury of 1 cm radius into 10% identical droplets. Surface tension of mercury is 35x10 N/m.
Answers
Answer:
Explanation:
Let the radius of the small droplets be r and ρ
be the density of mercury
Mass of the drop must be equal to the total mass of the droplets.
Therefore,
After putting it into the formula we get,
ρ×4π3R3=N×4π3r3×ρ
On simplifying the equation, we get,
⇒R3=Nr3
We can calculate the change in surface area by,
ΔA=N×4πr2−4πR2
On subtracting we get,
ΔA=4π(Nr2−R2)
Therefore,
From here we can calculate the energy spent,
Hence, energy spent is.
E=TΔA
On putting the values in the equation, we get,
E=4πT(Nr2−R2)
Therefore, after simplifying and substituting the values in the equation we the above answer.
Additional Information:
Surface tendency is the referred to as the tendency of the liquid surfaces to shrink into the minimum surface area possible. At liquid-air interfaces, surface tension results from the greater attraction of all liquid molecules to each other due to cohesion than to the molecules in air due to the process of adhesion. Surface tension, therefore, has the dimension of force per unit length, of energy per unit area. Thus, while referring to liquids the terms surface tension is generally used.