Question

find the eq of line perpendicular to line x-2y+3=0 and passing through point (1,-2).​

Answer 1

Step-by-step explanation:

x-2y+3=0

x=-2y+3

let take y=-2

then x=-2(-2)+3

=4-3

x=1

now let take y=2

then x=-2(2)+3

=-4+3

x=-1

now let take y=-1

then x=-2(-1)+3

=1+3

x=4

now let take y=1

then x=-2(1)+3

=-2+3

x=-1

this is your answer