Find the eqn of point which is at a distance of 5 from (_2'3)
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Answer:
Find the equation of the locus of a point which is at a distance 5 from (-2,3), in the xoy plane. 1. See answer. Add answer answer please make me brainlist
Answered by
1
Answer:
Let our point be (x,y)
Distance of any point from x-axis = magnitude of its y coordinate
From the question we have,
Distance of any point from x-axis =5
Which implies that
y =5
Now squaring each side we get
y² =25 which can be re-written as
y² −25=0.
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