Question

Find the eqn passing through points *(4,-5),(-1,-2)......
aabe suno jise answer pata hai.... wahi answer dena.....
NAHI TOOO......​

Answer 1

Given:

1st point = ( x1, y1 ) = (4,-5)

and

2nd point = (x2, y2) = (-1,-2)

Equation of line passing through two point is given by :-

$(y-y1) = \frac{(y2 - y1)}{(x2 - x1)}(x - x1)$

putting values we get :-

-5(y + 5) = 3(x - 4)

-5y -25 = 3x -12

3x + 5y +13 = 0

which is required equation of line.

Answer 2

||✪✪ QUESTION ✪✪||

Find the equation of line passing through points *(4,-5),(-1,-2)......?

|| ✰✰ ANSWER ✰✰ ||

❁❁ Refer To Image First .. ❁❁

From image , we can see that, we Proved a general formula to Find the Equation of line passing Through two points (x₁ , y₁) and (x₂ , y₂) :--

☙☘ (y - y₁) = (x - x₁) [ (y₂ - y₁) / (x₂ - x₁) ] ☘☙

__________

Given That :-

→ x₁ = 4

→ y₁ = (-5)

→ x₂ = (-1)

→ y₂ = (-2)

Putting all Values in Our Formula now, we get :-

☛ [ y - (-5) ] = ( x - 4) [ {(-2) - (-5)} / {(-1) - 4} ]

☛ (y + 5) = (x - 4) [ (5 -2) / (-5) ]

Cross - Multiplying ,

☛ (-5) * (y+5) = (x - 4) * 3

☛ (-5)y - 25 = 3x - 12

☛ 3x + 5y = (-25) + 12

☛ 3x + 5y = (-13)

☛ 3x + 5y + 13 = 0.

Hence, The Equation of The line That passes Through Points (4,-5),(-1,-2) is 3x + 5y + 13 = 0.