Question

find the equ
$2y {}^{2} + 4y + 12$
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Answer 1

Answer:

▶Here your answer

$2 {y}^{2} + 4y + 12 = 0 \\ \\ 2( {y}^{2} + 2y + 6) = 0 \\ \\ {y}^{2} + 2y + 6 = 0 \\ \\ y(y + 2) + 6 = 0 \\ \\ y = - 2 \: and \: - 6$