Question

find the equatin of the straight line containing the points (2,-3) and(0,-3)​

Answer 1

Answer:

We shall use the general equation

y = mx + c

(2 ,-3 ) is a point on the line.

∴ -3 = 2m +c. ———1

( 0,-3 ) is a point on the line

-3 = 0 + c

∴ c = -3 . ——-2

From (1) m = 0 .

Thus the equation is y = 0 -3 or y + 3 = 0

Step-by-step explanation:

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