Question

find the equation 13(y -- 4) - 3(y - 9) = 5 (y + 4)
2)4(2y - 3) + 5(3y - 4) = 14​

Answer 1

Answer:

13(y-4)-3(y-9)-5(y+4)=0

13y-52-3y+27-5y-20=0

13y-3y-5y-52-20+27=0

5y-45=0

5y=45

Y=45/5

Y=9

Answer 2

Answer:

Now, find the value of y by considering the above equation,

= 13y – 3y – 5y – 52 + 27 – 20 = 0 = 13y – 8y – 72 + 27 = 0 = 5y – 45 = 0

Transposing -45 to RHS and it becomes 45 = 5y = 45

Multiplying both side by (1/5) = 5y × (1/5) = 45 × (1/5) = y = 9

By substituting 9 in the place of y in given equation,

we get LHS, = 5y – 45 = 5 × (9) – 45 = 45 – 45 = 0 RHS, = 0

By comparing LHS and RHS = 0 = 0 ∴ LHS = RHS

Hence, the result is verified.