find the equation: 2 ( \frac { 3 x - 5 } { x + 2 } ) - 5 ( \frac { x + 2 } { 3 x - 5 } ) = 3 , x \neq - 2 x \neq \frac { 5 } { 3 }
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First, we have to find the lowest common denominator (LCD)
We recognize, that three of the denominators are multiples of (x-5)
x-5
2x-10=2(x-5)
6x-30= 6(x-5)
Now, we see, that 6(x-5) is their LCD.
We summarize these three fractions.
6x6(x−5)+3∗36(x−5)−1−x6(x−5)
=6x+9–1+x6(x−5)=7x+86(x−5)
When we look at the last fraction, we see, that its denominator is a multiple of three:
15–3x=3(5-x)
Now we change the sign:
(5-x)=-(x-5)
We get:
15–3x=-3(5-x)
The entire fraction is:
7−3(x−5)=−73(x−5)=146(x−5)
7x+86(x−5)−146(x−5)=7x−66(x−5)=1
Now, we multiply by 6(x+5)
7x-6=6(x+5)
7x-6=6x+30
We subtract 6x and add 6 on both sides:
x=36
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hope its will help yoy
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