Question

find the equation 3x + 2(X + 2) = 20 - (2x - 5) ​

Answer 1

Step-by-step explanation:

Hey there!

Solution:

\begin{gathered}3x + 2 ( x + 2 ) = 20 - ( 2x - 5 ) \\ \\ 3x + 2x + 4 = 20 - 2x + 5 \\ \\ 5x + 4 = 20x - 2x + 5\\ \\ 5x + 2x = 20 - 4 + 5 \\ \\ 7x = 16 + 5 \\ \\ 7x = 21 \\ \\ x = \frac{21}{7} \\ \\ x = 3 \\ \\ \textbf{To Check this} : \\ \\ Put x = 2 \\ \\ 3 ( 3 ) + 2 ( 3 + 2 ) = 20 - {2 ( 3 ) - 5 } \\ \\ 9 + 2 (5) = 20 - ( 6 - 5)\\ \\ 9 + 10 = 20 - 1 \\ \\19 = 19 \end{gathered}

3x+2(x+2)=20−(2x−5)

3x+2x+4=20−2x+5

5x+4=20x−2x+5

5x+2x=20−4+5

7x=16+5

7x=21

x=

7

21

x=3

To Check this:

Putx=2

3(3)+2(3+2)=20−2(3)−5

9+2(5)=20−(6−5)

9+10=20−1

19=19

Answer 2

Step-by-step explanation:

The above question can be written as,

= 3x + 2x + 4 = 20 – 2x + 5

Now, find the value of x by considering the above equation, = 5x + 4 = 20 – 2x + 5

Transposing 4 to RHS and it becomes

-4 and -2x to

LHS it becomes

2x = 5x + 2x

= 20 – 4 + 5

= 7x = 25 – 4 = 7x = 21

Multiplying both side by (1/7) = 7x × (1/7) = 21 × (1/7) = x = 21/7 = x = 3

By substituting 3 in the place of x in given equation, we get

LHS, = 5x + 4

= 5 × (3) + 4

= 15 + 4 = 19

RHS,

= 20 – 2x + 5 = 20

– 2 × (3) + 5 = 20 – 6 + 5

= 25 – 6 = 19

By comparing LHS and RHS = 19 = 19

∴ LHS = RHS

Hence, the result is verified.