Question

Find the equation equation of straight line joining point (3, 2) and making positive equal intercepts on axes.​

Answer 1

Answer:

0

Step-by-step explanation:

Equation of line is intercept from is  

xa

​y t  

=1

It passes through (−3,8)

a −3  +  y8

=1

a+b=7

b=7−a

a −3 +  7−a 8 =1

a  2 +7a−21=0

(a−3)(a+7)=0

a=−3,7

For positive intercept =a=3

⇒b=4

So the equation of line is

3 x  +  4 y

​ =1

4x+3y−12=0