Math, asked by alvairis1995, 1 year ago

Find the equation for the line that passes through the point (1,−5), and that is perpendicular to the line with the equation y=13x−23.

y=- 1/3x-2/3

Ankitgodara20: hi

Answers

Answered by brunoconti

Answer:

Step-by-step explanation:

Attachments:

alvairis1995: Find the equation for the line that passes through the point (4,−3), and that is perpendicular to the line with the equation y=23x+53.

y=2/3x + 5/3

souhit12: slope of the line will be -3/2as it is perpendicular to the given line

souhit12: then by point slope form y-(-3)=(-3/2)×(x-4)

souhit12: implies required equation will be 3x+2y=6

alvairis1995: 3x+2y=6 would be the equation right?

souhit12: yes

alvairis1995: Find the equation for the line that passes through the point (3,4), and that is parallel to the line with the equation y+4=−12(x+1).

y+4= -1/2(x+1)

souhit12: x+2y=11

Answered by souhit12

slope of the line is-3

by point slope form

y+5=(-3)×(x-1)

implies 3x+y+2=0

alvairis1995: x+2y=11 thats the equation?

souhit12: yes

alvairis1995: thank you

souhit12: Can u plz explain Jahn Teller effect in high spin complexes

alvairis1995: do you mind helping me on another question. please.

souhit12: no not at all but plz answer mine one if u can

souhit12: plz be fast or else post ur question I will answer it whenever I will get time

alvairis1995: i posted

alvairis1995: i posted your answer already

souhit12: where have u posted I cannot get it plz help

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Find the equation for the line that passes through the point (1,−5), and that is perpendicular to the line with the equation y=13x−23. y=- 1/3x-2/3

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Find the equation for the line that passes through the point (1,−5), and that is perpendicular to the line with the equation y=13x−23.

y=- 1/3x-2/3