Find the equation for the line that passes through the point (1,−5), and that is perpendicular to the line with the equation y=13x−23.
y=- 1/3x-2/3
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Find the equation for the line that passes through the point (4,−3), and that is perpendicular to the line with the equation y=23x+53.
y=2/3x + 5/3
y=2/3x + 5/3
slope of the line will be -3/2as it is perpendicular to the given line
then by point slope form y-(-3)=(-3/2)×(x-4)
implies required equation will be 3x+2y=6
3x+2y=6 would be the equation right?
yes
Find the equation for the line that passes through the point (3,4), and that is parallel to the line with the equation y+4=−12(x+1).
y+4= -1/2(x+1)
y+4= -1/2(x+1)
x+2y=11
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slope of the line is-3
by point slope form
y+5=(-3)×(x-1)
implies 3x+y+2=0
x+2y=11 thats the equation?
yes
thank you
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