Find the equation in Cartesian and vector form of the right bisector plane of the line segment joining
the points (a,a,a) and (-a,-a,-a).
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good question but idk
Step-by-step explanation:
sorry
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Step-by-step explanation:
Here First we will Find out the mid point of line segment AB joining the Pts A(a,a,a) and B(-a,-a,-a). After than direction of Vetor AB is the direction of Normal to the required plane. Than by using the formula find the equation of the Plane . It's easyy
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