Question

Find the equation (in general form) of the straight line passing through (0,3) and with slope 2.

Answer 1

Answer:

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Step-by-step explanation:

$so \: here \\ slope \: (m) = 2 \\ given \: points \: are \: (0,3) \\ so \: let \: (x1,y1) = (0,3)$

$now \: using \: equation \: of \: slope - intercept \: form \\ we \: get \\ (y - y1) = m(x - x1) \\ = (y - 3) = 2(x - 0) \\ = y - 3 = 2x - 0 \\ ie \: \: 2x - y + 3 = 0$

$hence \: equation \: (in general form) \: of \: the \: straight \: line \: passing \: through \: (0,3) \: and \: with \: slope \: 2. \: is \: 2x - y + 3 = 0$

Answer 2

Answer:

$\green{ \boxed{ \bf \: y = 2x + 3}}$

Step-by-step explanation:

If any straight line passing through ( a,b) point and with the slope = m, then its equation is :

$\bf \: y - b = m(x - a)$

According to the question, the straight line passing through ( 0,3) and with slope 2

so,

a = 0

b = 3

m = 2

So the equation is :

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \: y - 3 = 2(x - 0) \\ \bf \implies \: y - 3 = 2x \\ \bf \implies \: y = 2x + 3$