Question

find the equation of a circle having center p,q and radius root of the equation q²-p²​

Answer 1

Step-by-step explanation:

x

2

+2ax−b

2

=0

Let roots be x

1

& x

2

x

1

+x

2

=

a

−b

=−2a

x

1

x

2

=

a

c

=−b

2

x

2

+2px−q

2

=0

Let roots be y

1

& y

2

y

1

+y

2

=−2p

y

1

y

2

=−q

2

Equation in diametric form is

x

2

+y

2

−(x

1

+x

2

)x−(y

1

+y

2

)y+x

1

x

2

+y

1

y

2

=0

x

2

+y

2

+2ax+2py−b

2

−q

2

=0