Question

Find the equation of a circle of radius 6 units and whose centre lies on the negative direction of x-axis at a distance of 4 units from the origin .

Answer 1

(x+4)^2+y^2=36
x
$x ^{2} + y ^{2} + 8x - 20 = 0$

Answer 2

radius (r) = 6
center lie on negative directon of x axis at distance of 4 so center =(-4,0)
equations of circle = (x-(-4))^2 + (y-0)^2= 6^2
x^2+16+ 8x + y^2 =36
x^2+y^2+8x-20=0

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