Find the equation of a circle passing through the points (0,0),(6,0),(0,8)
Answers
Answered by
1
Answer:
x²+y²-6x-8y=0
Step-by-step explanation:
the given points form a right angled triangle in a circle, so the center of the circle is the mid point of its hypotenuse
center is (3,4)
radius is √(3-0)²+ (4-0)². = 5
equation of circle is
(x-h)²+(y-k)²=r²
(x-3)²+(y-4)²= 5²
x²+y²-6x-8y=0
Similar questions