Question

find the equation of a circle touching both the axes and whose radius is 5​

Answer 1

Answer:

Please see the attachment

Answer 2

The equation of the circle is x² -10x + y² -10y + 25 = 0

Step by Step Explanation:

It has been given that the circle touching both the axes and whose radius is 5​.

So,

r = 5

And let the the circle is at first quadrant.

So, radius of the circle is (5, 5)

The standard form of a circle is given by

(x-h)² + (y-k)² = r²

Substituting the known values in the formula

(x-5)² + (y-5)² = 5²

x² - 10x + 25 + y² - 10y+ 25  = 25

x² -10x + y² -10y + 25 = 0

#Learn More:

Find the equation of a circle with radius 5 whose centre lies on x axis and passes through the point (2,3)

https://brainly.in/question/47905