Question

find the equation of a circle which has the points - 2, 3 and 0, -1 as opposite ends of a diameter .​

Answer 1

Step-by-step explanation:

$hello... \\ \\ always \: remember.. \\ \\ if \: two \: ends \: of \: diameter \: are \: \\ given \: then \: use \: diametric \: form.. \\ \\ (x - x1)(x - x2) + (y - y1)(y - y2) = 0 \\ (x + 2)(x - 3) + y(y + 1) = 0 \\ {x}^{2} - x - 6 + {y}^{2} + y \\ \\ so \: required \: eqation \: is = > \\ {x}^{2} + {y}^{2} - x + y - 6 = 0 \\ \\ \\ hope \: it \: helps \: uh...$

Answer 2

Answer:

2x+y-1=o

we have to apply two point form of eq. of straight line