Math, asked by divi2003, 7 months ago

Find the equation of a circle which passes through (2, -3), and (-4, 5) and having the centre on 4x+3y+1=0

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Answered by ambicaomm

Answer:Equation of given circle, x2 + y2 + 4x + 6y + 11 = 0 The concentric circle will have the equation x2 + y2 + 4x + 6y + d = 0 ….(1) As it passes through P(5, 4), Put x = 5 and y = 4 52 + 42 + 20 + 24 + d= 0 25 + 16 + 20 + 24 + d = 0 d = – 85 Equation (1) ⇒ x2 + y2 + 4x + 6y – 85 = 0

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