Find the equation of a circle which touches y-axis at a distance of 4 units from the origin and cuts an intercept of 6 units along the positive direction of x- axis.
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Thank you for asking this question. Here is your answer:
Given:
PQ = 6 units
OM = 4 units
QN = PN = 3 Units
CN = MO = 4 Units
CQ² = QN² + NC²
CQ = √ 3² + 4²
= 5 units
Now CQ = CM = radius = 5 units
co - ordinate of C = (5,4)
and radius = 5 units so the equation of circle would be :
(x - 5)² + (y-4)² = 5²
x² + y² - 10x - 8y + 41 - 25 = 0
x² + y² - 10x - 8y + 16 = 0
If there is any confusion please leave a comment below.
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