find the equation of a circle whose centre is (3,5) and radius is 4
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equation of a circle is given by (x-a)^2 + (y-b)^2 = r^2
where a,b are the co-ordinates and r is the radius.
given (3,5) as the co-ordinate, we have
(x-3)^2+(y-5)^2 = 16
where a,b are the co-ordinates and r is the radius.
given (3,5) as the co-ordinate, we have
(x-3)^2+(y-5)^2 = 16
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