Question

find the equation of a circle whose radius is 5 unit and which cut off intercept 4 and 6 from the x and y axes

Answer 1

Answer:

The final answer is $(x-4)^2+(y-6)^2=25$

Explanation:

Given,

We have a circle of radius 5 unit and the circle has cut off intercepts at 4 in the x axis and at 6 in the y axis. We need to find the equation of the circle which satisfies the above constraints.

We know that the equation of a circle is : -

$x^2 + y^2 = r^2$

where x denotes the x axis and y denotes the y axis and r denotes the radius of the circle. If there is some intercept in the axes then it will be changed to

$(x-a)^2 + (y-b)^2=r^2$

Where a is the x intercept and b is the y intercept.

Substituting the values in the equation we get,

$(x-4)^2+(y-6)^2=5^2$

$(x-4)^2+(y-6)^2=25$

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