Question

Find the equation of a line !!!​

Answer 1

Answer:

you can do it by ur own by following these steps!

Step-by-step explanation:

Steps to find the equation of a line from two points:

Find the slope using the slope formula. ...

Use the slope and one of the points to solve for the y-intercept (b). ...

Once you know the value for m and the value for b, you can plug these into the slope-intercept form of a line (y = mx + b) to get the equation for the line.

Answer 2

u can see attachment too.

We know that, If p is the length of the normal from origin to a line and w is the angle made by the normal with the positive direction of x-axis then the equation of the line is given by xcosw+ysinw=p.

We know that, If p is the length of the normal from origin to a line and w is the angle made by the normal with the positive direction of x-axis then the equation of the line is given by xcosw+ysinw=p.Here, p=5 units and w=30∘

We know that, If p is the length of the normal from origin to a line and w is the angle made by the normal with the positive direction of x-axis then the equation of the line is given by xcosw+ysinw=p.Here, p=5 units and w=30∘Thus, the required equation of the given line is 

We know that, If p is the length of the normal from origin to a line and w is the angle made by the normal with the positive direction of x-axis then the equation of the line is given by xcosw+ysinw=p.Here, p=5 units and w=30∘Thus, the required equation of the given line is xcos30∘+ysin30∘=5

We know that, If p is the length of the normal from origin to a line and w is the angle made by the normal with the positive direction of x-axis then the equation of the line is given by xcosw+ysinw=p.Here, p=5 units and w=30∘Thus, the required equation of the given line is xcos30∘+ysin30∘=5⇒x23+y.21=5

We know that, If p is the length of the normal from origin to a line and w is the angle made by the normal with the positive direction of x-axis then the equation of the line is given by xcosw+ysinw=p.Here, p=5 units and w=30∘Thus, the required equation of the given line is xcos30∘+ysin30∘=5⇒x23+y.21=5⇒3x+y=10