Question

Find the equation of a line containing the points (1,2) and (3,8).​

Answer 1

Answer:

use the formula y = mx + c

where 'm' is gradient

'c' is the y intercept

 In points (1,2) and (3,8)

x1 = 1              x2 = 3

y 1= 2             y2 =  8

 find the gradient

 m =  y2-y1/x2-x1

so m=    8-2/3-1

which is 6/2 = 3

substitute 'm' as 3 in the equation

y = 3x + c    

now take any one point so, let us take (1,2)

substitute x as 1 and y as 2 in the equation

y = 3x + c

2 = 3(1)+ c

2 = 3 + c

2-3= c

-1=3

lets make the final equation

y = 3x -1

Answer 2

Answer:

Q 9) Write the cell address of the following:

1. Last row, last column

2. 21th row, 13th column

3. 18th row, 61th column

4. 50th row, 2nd last column

5. First row, 15th columnnjr

Step-by-step explanation: