Question

find the equation of a line having intercepts a , b on the axes sich that a+b =5, ab= 6.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$equation \: of \: line \: \: is \: \: \frac{x}{2} + \frac{y}{3} = 1 \: \: \: \: or \: \: \: \frac{x}{3} + \frac{y}{2} = 1.$

Step-by-step explanation:

$a + b = 5 \\ \\ ab = 6 \\ \\ a + \frac{6}{a} = 5 \\ \\ {a}^{2} - 5a + 6 = 0 \\ \\ {a}^{2} - 3a - 2a + 6 = 0 \\ \\ a(a - 3) - 2(a - 3) = 0 \\ \\ (a - 2)(a - 3) = 0 \\ \\ therefore \: \: \: a = 2 \: \: or \: \: a = 3. \: \: then \: b = 3 \: or \: b = 2 \\ \\ therefore \: \: \: equation \: of \: line \: \: is \: \: \frac{x}{2} + \frac{y}{3} = 1 \: \: \: \: or \: \: \: \frac{x}{3} + \frac{y}{2} = 1.$