find the equation of a line in y=mx+b, with equal intercepts and passing through the point (-3,-2)
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Answer:
Equation formed by Two intercepts is
a
x
+
b
y
=1
Given that, a=b
Since the line is passing through the point (2,3)
So,
a
2
+
a
3
=1
⟹
a
5
=1
∴a=5
Hence, b=5
The equation of the line is
5
x
+
5
y
=1 (or) x+y−5=0
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