Question

Find the equation of a line passe through the point (3.-4) and having slope -5/7​

Answer 1

Step-by-step explanation:

We know that the equation of line passing through point (x

0

,y

0

) whose slope is m is

(y−y

0

)=m(x−x

0

)

Thus the equation of line passing through the point (−4,3) whose slope is

2

1

is,

(y−3)=

2

1

(x+4)

⇒2(y−3)=(x+4)

⇒x−2y+10=0

Answer 2

Answer:

hey here is your solution

pls mark it as brainliest

Step-by-step explanation:

$so \: her e\: given \: points \: are \\ (3, - 4) \\ \\ let \: then \\ (3, - 4) = (x1,y1) \\ \\ slope \: (m) = \frac{ - 5}{7} \\ \\ we \: know \: that \\ slope \: point \: equation \: of \: straight \: line \\ is \: given \: by \\ \\ (y - y1) = m(x - x1) \\ \\ (y - ( - 4) = \frac{ - 5}{7} (x - 3) \\ \\ 7(y + 4) = - 5(x - 3) \\ \\ 7y + 28 = - 5x + 15 \\ \\ 5x + 7y + 13 = 0 \: \: \\ \\ or \: \\ \\ \: 5x + 7y = - 13$