Find the equation of a line passing through (0,4) and (5,6)
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Answer:
y = (2/5)x + 4
Step-by-step explanation:
Let y2 = 6, y1 = 4, x2 = 5, x1 = 0 Remember that points will always be given in the format (x, y)
Slope (m) = (y2 - y1) / (x2 - x1)
Slope (m) = (6 - 4) / (5 - 0)
Slope (m) = 2 / 5
y = mx + b
I will be using the point (5, 6) to find the value of b.
6 = (2/5) 5 + b
6 = 2 + b
4 = b
Hence,
y = (2/5)x + 4
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