Question

find the equation of a line passing through (2,-3) and parallel to 3x-2y+5=0​

Answer 1

Answer:

0

Step-by-step explanation:

What is the equation of the line passing through (2, -3) and is parallel to the line 3x+y=5?

First, we find the slope of the given line 3x+y−5=0 by using slope formula i.e.

m=−a/b

Where a is the coefficient of x & b is the coefficient of y.

m=−3/1

m=−3

As,

Required line ∥ given line

m'=m

m'= −3

Where m’ is the slope of required line.

Here,

(x1,y1)=(2,−3)

m′=−3

BY USING SLOPE-POINT FORMULA:

y−y1=m′(x−x1)

y−(−3)=(−3)(x−2)

y+3=−3x+6

3x+y+3−6=0

3x+y−3=0 Ans.

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Answer 2

Answer:

Happy to help

Step-by-step explanation:

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