Question

Find the equation of a line passing through the point (-2, 3) and parallel to x+y+1=0​

Answer 1

Solution:-

As we know that,

• The equation of of a line parallel to ax + by + c = 0 and passing through (x_1,y_1) is a(x - x_1) + b(y - y_1) = 0.

Where,

• x_1 = -2
• y_1 = 3
• a = 1
• b = 1
• c = 1

Putting the values,

$\\ \implies\sf{1\bigg(x -(-2)\bigg)+1\bigg(y-3\bigg) = 0} \\ \\ \implies \sf{1(x + 2) + 1(y - 3) = 0 } \\ \\ \implies \sf{x + 2 + y - 3 = 0} \\ \\ \implies \sf{x + y - 1 = 0}$

• Hence,the equation of the line is x + y - 1 = 0.