Question

find the equation of a line passing through the point (-2, 5) and parallel to the line 3y+7x=29

Answer 1

Answer:

$3y+7x=29$

$(-2, 5)$

Answer 2

Answer:

x-3y+9=0

Rearranging,

y=x/3 + 3.

the gradient m is 1/3 when compared to the eqn of a straight line y=mx+c.

when two lines are parallel, their gradients are equal therefore the eqn of the line that passes through point (-1,4) and parallel to the line x-3y+9=0 is

y-4=1/3[x-(-1)]

y-4=1/3(x+1)

3y-12=x+1

3y-x-13=0.