Question

Find the equation of a line passing through the point (2012,2014) and ( 2013,2015)​

Answer 1

Answer:

y=x+2

Step-by-step explanation

slope = (y2-y1)/(x2-x1)

(x1,y1) = (2012,2014)

(x2,y2)=(2013,2014)

⇒slope =1

plug this in y=mx+c (with any point let it be (2012,2014)

from here we have c=2

hence equation is y=x+2