Question

Find the equation of a line passing through the point ( -4,3 ) and having slope -7/5

Answer 1

Answer:

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Answer 2

Answer:

The equation of the required line is found to be $7x+5y=-13$.

Step-by-step explanation:

The point through which the given line passes through is given as:

(x,y) = (-4,3)

The slope of the same line is given to us as:

m = $\frac{-7}{5}$

We know that the general form for a straight line is: $y=mx+c$

Substituting $m,x,y$ in this, we get:

$3=\frac{-7(-4)}{5}+c$

Simplifying it, we get:

$3\times 5=28+5c$

$15-28=5c$

or we can say:

$c=-\frac{13}{5}$

Now, substituting the value of m and c in the general form, we get:

$y=-\frac{7}{5}x-\frac{13}{5}$

Simplifying it, we get:

$y=\frac{-7x-13}{5}$

$-5y=7x+13$

Seperating the variables, we get:

$7x+5y=-13$

Thus, it is the required answer.