find the equation of a line passing through the point(-4,3) and having slope -7/5
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Answered by
1
Step-by-step explanation:
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Answered by
9
Answer:
7x+5y+13=0
Step-by-step explanation:
(x1,y1)=(-4,3)
m=-7/5
the equation of straight line which has (x1,y1) and slope m
(y-y 1)=m(x-x 1)
(y-3)=-7/5(x+4)
5(y-3)=-7(x+4)
5y-15=-7x-28
7x+5y+13=0
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