Find the equation of a line passing through the point (-4,6) and having the x-intercept of 8 units.
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Answers
Answered by
14
x intercept is 8
I.e point is (8,0)
and given point is (-4,6)
hence, the equation is
(y-0)=0-6/[8-(-4)] (x-8)
y = -6/12 (x-8)
12y= -6x+48
6x+12y=48
dividing by 6
we get x+2y=8
I.e point is (8,0)
and given point is (-4,6)
hence, the equation is
(y-0)=0-6/[8-(-4)] (x-8)
y = -6/12 (x-8)
12y= -6x+48
6x+12y=48
dividing by 6
we get x+2y=8
smitesh:
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Answered by
7
we have x intercept=8-(8,0)
line passes through =(-4,6)
equation of line
y-0=6-0/-4-8(x-8)
-12y=6x-48
6x+12y-48
line passes through =(-4,6)
equation of line
y-0=6-0/-4-8(x-8)
-12y=6x-48
6x+12y-48
can you tell answer only . i will explain it again
but i still appreciate ur efforts thanks
the answer is given this one only
x+2y=8
which
ok
ya
Wait i send you the best answet
okay u can write it once again
actually i had also done the same mistake
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