Question

find the equation of a line passing through the point P(-2,1) and parallel to the line joining the points A(4,-3) and B(-1,5).​

Answer 1

Answer:

Slope of line = Slope of AB =

$\frac{5 + 3}{ - 1 - 4} = - \frac{8}{5}$

Eq. of line is

$(y - 1) = - \frac{8}{5} (x + 2)$

$5y - 5 = - 8x - 16$

$8x + 5y + 11 = 0$

Answer 2

Answer:

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