Find the equation of a line that passes through the point (-3,2) and has a gradient of
1/2
Leave your answer in the form
y= mx+c
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Answer:1) The general form of the equation of a line is y = mx+c.
If the line has a gradient 3 (which is m here) and passes through (2,1) which is (x,y) here, we can find c the intercept on the y-axis as
1 = 3*2+ c, or
c = 1-6 = -5.
So the equation of the line you are seeking is
y = 3x-5.
2) An intercept of 3 on the x-axis - in point (3,0)
An intercept of 4 on the y-axis - in point (0,4)
\dfrac{x-x_a}{x_b-x_a}=\dfrac{y-y_a}{y_b-y_a} \\ \dfrac{x-3}{0-3}=\dfrac{y-0}{4-0}\\ \dfrac{x-3}{-3}=\dfrac{y}{4}\\ answer: y=-\dfrac{4}{3}x+4
x
b
−x
a
x−x
a
=
y
b
−y
a
y−y
a
0−3
x−3
=
4−0
y−0
−3
x−3
=
4
y
answer:y=−
3
4
x+4
Step-by-step explanation:
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