find the equation of a line through (-4,5)and perpendicular to line 5x-3y=4
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Answer:
3x+5x+5=0
Step-by-step explanation:
slope(m₁)=-(coefficient of coordinates/coefficient of abscissa)
slope(m₁)=- (-3/5)
slope(m₁)=3/5
m₁m₂=-1....................................................(m₁)=3/5
m₂=-5/3
formula of a equation=y-y₁=m(x-x₁)
y-5=-5/3(x-(-4)
3y-15=-5x+(-20)
3x-15=-5x-20
3x+5x+5=0
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